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3x^2/2=486
We move all terms to the left:
3x^2/2-(486)=0
We multiply all the terms by the denominator
3x^2-486*2=0
We add all the numbers together, and all the variables
3x^2-972=0
a = 3; b = 0; c = -972;
Δ = b2-4ac
Δ = 02-4·3·(-972)
Δ = 11664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{11664}=108$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-108}{2*3}=\frac{-108}{6} =-18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+108}{2*3}=\frac{108}{6} =18 $
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